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__Time and work - Aptitude Important Formulas, Shortcut Methods and Tricks__:

__Time and work - Aptitude Important Formulas, Shortcut Methods and Tricks__:

1. If ‘A’
can do a piece of work in ‘a’ days, then work performed in one day = 1/a part
of work.

2. If A’s 1
day's work = (1/a), then ‘A’ can finish the work in ‘a’ days.

3. A is
thrice as good a workman as B, then:

Ratio of work done by A and B = 3
: 1.

Ratio of times taken by A and B
to finish a work = 1 : 3.

4. If ‘A’ is
‘x’ times as good as work performed as B, then time taken by A = (1/x)th time
taken by ‘B’.

5. If ‘A’
and ‘B’ can do a piece of work in ‘x’ and ‘y’ days respectively, then time
taken with working together =

*xy/(x + y)*days.
6. If the
number of men to do a job is changed in the ratio a : b, then the time required
to do the work will be changed in the ratio b : a.

7. If two
men ‘A’ and ‘B’ together can finish a job in ‘x’ days and if ‘A’ working alone
takes ‘a’ days more than “A and B” working together and ‘B’ working alone takes
‘b’ days more than “A and B” working together,

then,

then,

*x = √ab*

__Example: 01__**A and B can do a work in 10 days, B and C can do the same work in 20 days, while C and A can do it in 15 days. In how many days can C alone do the same work?**

__Solution:__
(A + B)’s 1
day’s work = 1/10

(B + C)’s 1
day’s work = 1/20

(C + A)’s 1
day’s work = 1/15

On adding,

2 (A + B +
C)’s 1 day’s work = [1/10 + 1/20 + 1/15] = [(6 + 3 + 4)/60] = 13/60

∴(A + B + C)’s 1
day’s work = 13/120

Now, C’s 1
day’s work = {(A + B + C)’s 1 day’s work} - {(A
+ B)’s 1 day’s work}

= (13/120) -
(1/10)

= (13 -
12)/120

= 1/120

Hence, C
alone can do the work in 120 days.

__Example: 02__**A and B could do a piece of work in 30 days. After working for 10 days, they are assisted by C and the work is finished in 10 days. If C does as much work in 2 days as B does in 3 days, in how many days could A do the same work alone?**

__Solution:__
(A + B)’s 1 day’s work = 1/30 ………………………….(i)

(A + B)’s 10 day’s work = 10 ×
(1/30) = 1/3

Remaining work = 1 - (1/3) = 2/3

Now, since (A + B + C)’s 10 day’s work = 2/3

∴(A + B + C)’s 1 day’s work = 2/(3 ×
10) = 1/15 ……………(ii)

∴ From
equation (ii) - (i), C’s 1 day’s work = (1/15) - (1/30) = 1/30

Hence, C can finish the work in 30
days.

Now, it is given that C does as much
work in 2 days as B does in 3 days.

∴ The work
which C does in 30 days, will be done by B in = 30 × (3/2) = 45 days.

Hence, B
alone can finish the work in 45 days.

∴ B’s 1 day’s work =
1/45 ……………………(iii)

From
equation (i) - (iii), A’s 1 day’s work =
(1/30) - (1/45) = 1/90

Therefore,
A alone can finish the work in 90 days.