Practice Test: Question Set - 02
1. The branch current method uses
- (A) Kirchhoff's
voltage and current laws
- (B) Thevenin's
theorem and Ohm's law
- (C) Kirchhoff's
current law and Ohm's law
- (D) The
superposition theorem and Thevenin's theorem
2. When assigning branch currents, you need not be concerned with the direction you choose.
- (A) True
- (B) False
3. Find the node voltage VA.
- (A) 6 V
- (B) 12 V
- (C) 4.25 V
- (D) 3 V
4. Second-order determinants are evaluated by subtracting the signed cross-products.
- (A) True
- (B) False
5. Find the node voltage VA.
- (A) 518 mV
- (B) 5.18 V
- (C) 9.56 V
- (D) 956 mV
6. The mesh current method is based on Kirchhoff's current law.
- (A) True
- (B) False
7. Using the mesh current method, find the branch current, IR1, in the above figure.
- (A) 115 mA
- (B) 12.5 mA
- (C) 12.5 A
- (D) 135 mA
8. The first row of a certain determinant has the numbers 10 and 6. The second row has the numbers 3 and 5. The value of this determinant is
- (A) 18
- (B) 50
- (C) 32
- (D) -32
9. The mesh method can be applied to circuits with any number of loops.
- (A) True
- (B) False
10. Find I1.
4I1 +
4I2 = 2
6I1 + 7I2 = 4
6I1 + 7I2 = 4
- (A) 0.5 A
- (B) 50 mA
- (C) -0.5 A
- (D) -50 mA
11. What is the current through R2?
- (A) 3.19 A
- (B) 319 mA
- (C) 1.73 A
- (D) 173 mA
12. What is the voltage drop across R2?
- (A) 3.5 V
- (B) 4.18 V
- (C) 1.5 V
- (D) 145 mV
13. Find I2.
4I1 +
4I2 = 2
6I1 + 7I2 = 4
6I1 + 7I2 = 4
- (A) 1 A
- (B) -1 A
- (C) 100 mA
- (D) -100 mA
14. Third-order determinants are evaluated by the expansion method or by the cofactor method.
- (A) True
- (B) False
15. What is the current through R2?
- (A) 177 mA
- (B) 250 mA
- (C) 500 mA
- (D) 125 mA
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