__Question No. 01__**It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?**

(A) Sunday

(B) Saturday

(C) Friday

(D) Wednesday

Answer: Option C

**Explanation:**

On 31

^{st}December, 2005 it was Saturday.Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

∴ On 31

^{st}December 2009, it was Thursday.Thus, on 1

^{st}Jan, 2010 it is Friday.

__Question No. 02__**What was the day of the week on 28**

^{th}May, 2006? (A) Thursday

(B) Friday

(C) Saturday

(D) Sunday

Answer: Option D

**Explanation:**

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = {(4 × 1) + (1 × 2)} ≡ 6 odd days

Jan. Feb. March April May

(31 + 28 + 31 + 30 + 28) = 148 days

∴ 148 days = (21 weeks + 1 day) ≡ 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 ≡ 0 odd day.

Given day is Sunday.

__Question No. 03__**What was the day of the week on 17**

^{th}June, 1998? (A) Monday

(B) Tuesday

(C) Wednesday

(D) Thursday

Answer: Option C

**Explanation:**

17

^{th}June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0

Odd days in 300 years = (5 × 3) ≡ 1

97 years have 24 leap years + 73 ordinary years.

Number of odd days in 97 years {(24 × 2) + 73} = 121 = 2 odd days.

Jan. + Feb. + March + April + May + June

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

∴ 168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

__Question No. 04__**What will be the day of the week 15**

^{th}August, 2010? (A) Sunday

(B) Monday

(C) Tuesday

(D) Friday

Answer: Option A

**Explanation:**

15

^{th}August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = {(2 × 2) + (7 × 1)} =
11 odd days ≡ 4 odd days.

Jan. + Feb. + March + April +
May + June + July + Aug.

(31 + 28 + 31 + 30 + 31 + 30 +
31 + 15) = 227 days

∴ 227 days = (32 weeks + 3 days) ≡ 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 ≡ 0 odd days.

Given day is Sunday.

__Question No. 05__**Today is Monday. After 61 days, it will be:**

(A) Wednesday

(B) Saturday

(C) Tuesday

(D) Thursday

Answer: Option B

**Explanation:**

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

∴ After 61 days, it will be Saturday.

__Question No. 06__**If 6**

^{th}March, 2005 is Monday, what was the day of the week on 6^{th}March, 2004? (A) Sunday

(B) Saturday

(C) Tuesday

(D) Wednesday

Answer: Option A

**Explanation:**

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March
2004 to March 2005. So it has 1 odd day only.

∴ The day on 6

^{th}March, 2005 will be 1 day beyond the day on 6^{th}March, 2004.Given that, 6

^{th}March, 2005 is Monday.∴ 6

^{th}March, 2004 is Sunday (1 day before to 6^{th}March, 2005).

__Question No. 07__**On what dates of April, 2001 did Wednesday fall?**

(A) 1

^{st}, 8^{th}, 15^{th}, 22^{nd}, 29^{th} (B) 2

^{nd}, 9^{th}, 16^{th}, 23^{rd}, 30^{th} (C) 3

^{rd}, 10^{th}, 17^{th}, 24^{th} (D) 4

^{th}, 11^{th}, 18^{th}, 25^{th} Answer: Option D

**Explanation:**

We shall find the day on 1

^{st}April, 2001.1

^{st}April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)Odd days in 1600 years = 0

Odd days in 400 years = 0

Jan. Feb. March April

(31 + 28 + 31 + 1) = 91 days ≡ 0
odd days.

Total number of odd days = (0 + 0 + 0) = 0

On 1

^{st}April, 2001 it was Sunday.In April, 2001 Wednesday falls on 4

^{th}, 11^{th}, 18^{th}and 25^{th}.

__Question No. 08__**How many days are there in**

*x*weeks*x*days? (A) 7

*x*^{2} (B) 8

*x* (C) 14

*x* (D) 7

Answer: Option B

**Explanation:**

*x*weeks

*x*days = (7

*x*+

*x*) days = 8

*x*days.

__Question No. 09__**The last day of a century cannot be**

(A) Monday

(B) Wednesday

(C) Tuesday

(D) Friday

Answer: Option C

**Explanation:**

100 years contain 5 odd days.

∴ Last day of 1

^{st}century is Friday.200 years contain (5 × 2) ≡ 3
odd days.

∴ Last day of 2

^{nd}century is Wednesday.300 years contain (5 × 3) = 15 ≡ 1
odd day.

∴ Last day of 3

^{rd}century is Monday.400 years contain 0 odd day.

∴ Last day of 4

^{th}century is Sunday.This cycle is repeated.

∴ Last day of a century cannot be Tuesday or Thursday or
Saturday.

__Question No. 10__**On 8**

^{th}Feb, 2005 it was Tuesday. What was the day of the week on 8^{th}Feb, 2004? (A) Tuesday

(B) Monday

(C) Sunday

(D) Wednesday

Answer: Option C

**Explanation:**

The year 2004 is a leap year. It has 2 odd days.

∴ The day on 8

^{th}Feb, 2004 is 2 days before the day on 8^{th}Feb, 2005.Hence, this day is Sunday.

__Question No. 11__**The calendar for the year 2007 will be the same for the year:**

(A) 2014

(B) 2016

(C) 2017

(D) 2018

Answer: Option D

**Explanation:**

Count the number of odd days from the year 2007 onwards to get the
sum equal to 0 odd day.

Sum = 14 odd days ≡ 0 odd days.

∴ Calendar for the year 2018 will be the same as for the year 2007

__Question No. 12__**Which of the following is not a leap year?**

(A) 700

(B) 800

(C) 1200

(D) 2000

Answer: Option A

**Explanation:**

The century divisible by 400 is a leap year.

∴ The year 700 is not a leap year.

__Question No. 13__**On 8**

^{th}Dec, 2007 Saturday falls. What day of the week was it on 8^{th}Dec, 2006? (A) Sunday

(B) Thursday

(C) Tuesday

(D) Friday

Answer: Option D

**Explanation:**

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8

^{th}Dec, 2007 will be 1 day beyond the day on 8^{th}Dec, 2006.But, 8

^{th}Dec, 2007 is Saturday.∴ 8

^{th}Dec, 2006 is Friday.

__Question No. 14__**January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?**

(A) Monday

(B) Wednesday

(C) Thursday

(D) Sunday

Answer: Option C

**Explanation:**

The year 2008 is a leap year. So, it has 2 odd days.

1

^{st}day of the year 2008 is Tuesday (Given)So, 1

^{st}day of the year 2009 is 2 days beyond Tuesday.Hence, it will be Thursday.

__Question No. 15__**January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?**

(A) Monday

(B) Tuesday

(C) Wednesday

(D) Sunday

Answer: Option B

**Explanation:**

The year 2007 is an ordinary year. So, it has 1 odd day.

1

^{st}day of the year 2007 was Monday.1

^{st}day of the year 2008 will be 1 day beyond Monday.Hence, it will be Tuesday.

**Calendar Aptitude: Next Tests**